quadr. Approx. ein?

φ beeinflusst 
die Matrix A

Richtungsfeld?

Fixpunkt

exakt ein?

c = (0.12181069958847708, 0.4659259259259251)
b = (0.7704346827447605, -0.2569574121925553)
φ = 0.8203047484373356 (slider from (-π) to π, step π / 180)
a = CurveCartesian((((cos(φ) * x(c)) - (sin(φ) * y(c)) + x(b)) * t), (((sin(φ) * x(c)) + (cos(φ) * y(c)) + y(b)) * t), t, 0, 2)
f(t) = x(a(t))
g(t) = y(a(t))
b_1 = CurveCartesian(x(c) + f(t), y(c) + g(t), t, 0, 2)
c_1 = CurveCartesian(x(c) + f(t) + (((f(t) * cos(φ)) - (g(t) * sin(φ))) * t / 2), y(c) + g(t) + (((f(t) * sin(φ)) + (g(t) * cos(φ))) * t / 2), t, 0, 2)
l1 = Sequence(CurveCartesian[((((-sin(φ)) * s / 10) + x(b)) * t), s / 10 + (((cos(φ) * s / 10) + y(b)) * t), t, 0, 5], s, 0, 10)
l2 = Sequence(CurveCartesian[((((-sin(φ)) * s / 10) + x(b)) * t) + (((((((-sin(φ)) * s / 10) + x(b)) * t) * cos(φ)) - ((((cos(φ) * s / 10) + y(b)) * t) * sin(φ))) * t / 2), s / 10 + (((cos(φ) * s / 10) + y(b)) * t) + (((((((-sin(φ)) * s / 10) + x(b)) * t) * sin(φ)) + ((((cos(φ) * s / 10) + y(b)) * t) * cos(φ))) * t / 2), t, 0, 5], s, 0, 10)
q = true
A = Intersect(xAxis, yAxis)
u = Vector(A, b)
v = Vector(A, c)
d = true
Steigungsfeld1 = SlopeField(((x * sin(φ)) + (y * cos(φ)) + y(b)) / ((x * cos(φ)) - (y * sin(φ)) + x(b)), 33, 1, -1.2, 0, 2, 3.2)
Fix: (((-x(b)) * cos(φ)) - (y(b) * sin(φ)), ((-y(b)) * cos(φ)) + (x(b) * sin(φ)))
e = CurveCartesian((-((y(b) * sin(φ)))) + ((ℯ^((t * cos(φ))) * cos((t * sin(φ)))) * (x(c) + (y(b) * sin(φ)))) - ((y(c) * ℯ^((t * cos(φ)))) * sin((t * sin(φ)))) + (((x(b) * ℯ^((t * cos(φ)))) * sin(φ)) * sin((t * sin(φ)))) + (cos(φ) * ((-x(b)) + ((x(b) * ℯ^((t * cos(φ)))) * cos((t * sin(φ)))) - ((y(b) * ℯ^((t * cos(φ)))) * sin((t * sin(φ)))))), (x(b) * sin(φ)) + ((ℯ^((t * cos(φ))) * cos((t * sin(φ)))) * (y(c) - (x(b) * sin(φ)))) + ((x(c) * ℯ^((t * cos(φ)))) * sin((t * sin(φ)))) + (((y(b) * ℯ^((t * cos(φ)))) * sin(φ)) * sin((t * sin(φ)))) + (cos(φ) * ((-y(b)) + ((y(b) * ℯ^((t * cos(φ)))) * cos((t * sin(φ)))) + ((x(b) * ℯ^((t * cos(φ)))) * sin((t * sin(φ)))))), t, 0, 3)
h = true
phi: (φ * 180 / π)
Text2: "\varphi=" + (LaTeX[phi]) + "°"
B = (1.5649191310173234, -0.3642721025935507)
C = (1.7487177720356026, -0.3642721025935507)